Mole ConceptMedium
Question
The number of hydrogen atoms present in 5.4 g of urea is:
(Given: Molar mass of urea : $60\text{ }g{\text{ }mol}^{- 1}$
$N_{A}:6.022 \times 10^{23}$ particles ${mol}^{- 1}$ )
Options
A.$1.084 \times 10^{23}$
B.$1.084 \times 10^{22}$
C.$2.168 \times 10^{22}$
D.$2.168 \times 10^{23}$
Solution
Sol. [Key Concept: Number of atoms from moles using Avogadro's number]
Structure of urea:
Mole of urea $= \frac{5.4}{60} = 0.09$
Number of hydrogen atoms $= 0.09 \times 4 \times 6.022 \times 10^{23}$
$$\begin{matrix} & \ = 2.1679 \times 10^{23} \\ & \ \simeq 2.168 \times 10^{23} \end{matrix}$$
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