Mole ConceptHard
Question
A 12 g sample of CH4 and C2H4 yielded 35.2 g of CO2 on complete oxidation. What was the mean molar mass of the original sample?
Options
A.20.0
B.22.0
C.14.7
D.23.0
Solution
Let CH4 = x mole and C2H4 = y mole
From question, x × 16 + y × 28 = 12 (1)
and from CO2, (x + 2y) × 44 = 35.2 (2)
Hence, x = 0.4 and y = 0.2
Now, $M_{av} = \frac{x + 16 + y \times 28}{x + y} = 20$
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