Mole ConceptHard
Question
The number of g-molecules of oxygen in 6.023 × 1024 CO molecules is
Options
A.1 g-molecule
B.0.5 g-molecule
C.5 g-molecules
D.10 g-molecules
Solution
Number of g-molecules of oxygen $= \frac{6.022 \times 10^{24}}{6.022 \times 10^{23}} \times \frac{1}{2} = 5$
Create a free account to view solution
View Solution FreeMore Mole Concept Questions
What is the percentage of ‘free SO3’ in a sample of oleum labelled as ‘104.5%’?...25 mL of an aqueous solution of KCl was found to require 20 mL of 1 M AgNO3 solution when titrated using a K2CrO4 as ind...When burnt in air, 14.0 g mixture of carbon and sulphur gives a mixture of CO2 and SO2 in the volume ratio of 2: 1, the ...In a textile mill, a double effect evaporator system concentrates weak liquor containing 4% (by mass) caustic soda to pr...A solution containing Cu2+ and C2O42- ions which is titrated with 20 ml of M/4 KMnO4 solution in acidic medium completel...