Chemical EquilibriumHard

Question

The amounts of 0.8 mol of PCl5 and 0.2 mole of PCl3 are mixed in a 1 L flask. At equilibrium, 0.4 mole of PCl3 is present. The equilibrium constant for the reaction, PCl5(g) $\rightleftharpoons$ PCl3(g) + Cl2(g) will be

Options

A.0.05 mol L–1
B.0.13 mol L–1
C.0.013 mol L–1
D.0.60 mol L–1

Solution

PCl5(g) $\rightleftharpoons$ PCl3(g) + Cl2(g)

0.8 mole 0.2 mole 0

Equilibrium 0.8 – x 0.2 + x x

= 0.6 = 0.4 = 0.2

∴ x = 0.2

Now, $K_{C} = \frac{\left\lbrack PCl_{3} \right\rbrack\left\lbrack Cl_{2} \right\rbrack}{\left\lbrack PCl_{5} \right\rbrack} = \frac{\left( \frac{0.4}{1} \right) \times \left( \frac{0.2}{1} \right)}{\left( \frac{0.6}{1} \right)} = 0.133\text{ M}$

Create a free account to view solution

View Solution Free
Topic: Chemical Equilibrium·Practice all Chemical Equilibrium questions

More Chemical Equilibrium Questions

For a reversible reaction $A\overset{\quad K_{1}K_{2}\quad}{\leftleftarrows}B$, the initial molar concentration of A and...At total pressure P1 atm and P2 atm, N2O4 is dissociated to an extent of 33.33% and 50.00%, respectively. The ratio of p...The following equilibrium are given CO + H2O ⇋ CO2 + H2 ----- K12H2 + O2 ⇋ 2H2O ------ K2then equilibrium co...In the decomposition equilibrium of a certain alkaline earth metal carbonate, the partial pressure of CO2 becomes a hund...An aqueous solution contains 0.10 M H2S and 0.20 M HCl. If the equilibrium constants for the formation of HS- from H2S i...