Chemical EquilibriumHard
Question
One mole each of A and B and 3 moles each of C and D are placed in 1 L flask. If equilibrium constant is 2.25 for the reaction A + B$\rightleftharpoons$C + D, then equilibrium concentrations of A and C will be in the ratio
Options
A.2:3
B.3:2
C.1:2
D.2:1
Solution
At equilibrium, [A] = [B] and [C] = [D] and hence
$K = \frac{\lbrack C\rbrack\lbrack D\rbrack}{\lbrack A\rbrack\lbrack B\rbrack} = \frac{\lbrack C\rbrack^{2}}{\lbrack A\rbrack^{2}} \Rightarrow \frac{\lbrack C\rbrack}{\lbrack A\rbrack} = \sqrt{2.25} $$$\Rightarrow 1.5 = \frac{\lbrack A\rbrack}{\lbrack C\rbrack} = \frac{2}{3}$$
Create a free account to view solution
View Solution FreeMore Chemical Equilibrium Questions
A gaseous substance AB2(g) converts to AB(g) in the presence of solid A as AB2(g) + A(s)$\rightleftharpoons$ 2AB(g).The ...Which of the following statements is correct for a reversible process in a state of equilibrium ?...Which of the following is/are correct statement(s)?...Which one of the following has lowest melting point :-...For the reaction SO2(g) + O2(g) ⇋ SO3(g), if KP = KC(RT)x where the symbols have usual meaning then the value of x...