Chemical EquilibriumMedium
Question
One mole each of A and B and 3 moles each of C and D are placed in 1 L flask. If equilibrium constant is 2.25 for the reaction A + B$\rightleftharpoons$C + D, then equilibrium concentrations of A and C will be in the ratio
Options
A.2:3
B.3:2
C.1:2
D.2:1
Solution
At equilibrium, [A] = [B] and [C] = [D] and hence
$K = \frac{\lbrack C\rbrack\lbrack D\rbrack}{\lbrack A\rbrack\lbrack B\rbrack} = \frac{\lbrack C\rbrack^{2}}{\lbrack A\rbrack^{2}} \Rightarrow \frac{\lbrack C\rbrack}{\lbrack A\rbrack} = \sqrt{2.25} $$$\Rightarrow 1.5 = \frac{\lbrack A\rbrack}{\lbrack C\rbrack} = \frac{2}{3}$$
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