Chemical EquilibriumHard
Question
1 mol of N2 is mixed with 3 mol of H2 in a litre container. If 50% of N2 is converted into ammonia by the reaction N2 + 3H2(g) ⇋ 2NH3(g), then the total number of moles of gas at the equilibrium are
Options
A.1.5
B.4.5
C.3.0
D.6.0
Solution
α = 50 % = 
= 0.5
N2 + 3H2 ⇋ 2NH3
Initial 1 3 0
Final 1 - α 3 - 3α 2α
Total moles = 1 - α + 3 - 3α + 2α
= 4 - 2α
= 4 - 2 × 0.5 = 3
= 0.5N2 + 3H2 ⇋ 2NH3
Initial 1 3 0
Final 1 - α 3 - 3α 2α
Total moles = 1 - α + 3 - 3α + 2α
= 4 - 2α
= 4 - 2 × 0.5 = 3
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