ElectrochemistryHard
Question
The oxidation states of sulphide in S8, S2F2, H2S respectively, are
Options
A.0, +1 and -2
B.+2, +1 and -2
C.0, +1 and +2
D.-2, 1 and -2
Solution
Oxidation number of S in S8 = 
= 0
Let oxidation number of S in S2F2 be x
2x +2(- 1) = 0 x=+1
in H2S 2 + x = 0
x = - 2
= 0Let oxidation number of S in S2F2 be x
2x +2(- 1) = 0 x=+1
in H2S 2 + x = 0
x = - 2
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