At 298 K, a certain buffer solution contains equal concentrations of $X^{-}$and $HX,K_{b}$ for $X^{-

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At 298 K, a certain buffer solution contains equal concentrations of $X^{-}$and $HX,K_{b}$ for $X^{-}$is $10^{- 10}$. What is the pH of this buffer solution?

Accepted Answer

Sol. [Key Concept: Basic buffer — pOH = pKb + log([salt]/[base])]$HX ightleftharpoons H^{+} + X^{-}$$${K_{a} 	imes K_{b} = K_{w} }{K_{a} = \frac{K_{w}}{K_{b}} = \frac{10^{- 14}}{10^{- 10}} = 10^{- 4} }{pH = {pK}_{a} + log\frac{\left\lbrack X^{-} ightbrack}{\lbrack HXbrack} }$$Given that : $\lbrack X - brack = \lbrack HXbrack$$$= 4 + log(1) $$= 4 + 0= 4

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