Ionic EquilibriumMedium
Question
Ag+ + NH3 $\rightleftharpoons$ [Ag(NH3)+]; K1 = 1.6 × 103
[Ag(NH3)+] + NH3 $\rightleftharpoons$ [Ag(NH3)2+]; K2 = 6.8 × 103
The formation constant of [Ag(NH3)2+] is
Options
A.1.08 × 107
B.6.08 × 106
C.1.08 × 103
D.1.08 × 105
Solution
$K_{f} = K_{f_{1}}.K_{f_{2}} = 1.6 \times 10^{3} \times 6.8 \times 10^{3} = 1.08 \times 10^{7}$
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