When the concentration of reactant in the reaction A → B is increased by 8 times, the rate increases

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When the concentration of reactant in the reaction A → B is increased by 8 times, the rate increases only by 2 times. The order of reaction is

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r = K.[A]n$	herefore\frac{r_{2}}{r_{1}} = \left( \frac{\left\lbrack A_{2} ightbrack}{\left\lbrack A_{1} ightbrack} ight)^{n} \Rightarrow 2 = (8)^{n} \Rightarrow n = \frac{1}{3}$

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