ThermodynamicsHard

Question

The volume of a system becomes twice its original volume on the absorption of 300 cal of heat. The work done on the surrounding was found to be 200 cal. What is ΔU for the system?

Options

A.500 cal
B.300 cal
C.100 cal
D.−500 cal

Solution

$\Delta U = q + w = ( + 300) + ( - 200) = 100\text{ cal}$

(Work is done by the system)

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