ThermodynamicsHard

Question

The heat capacity of liquid water is 75.6 J/K-mol, while the enthalpy of fusion of ice is 6.0 kJ/mol. What is the smallest number of ice cubes at 0°C each containing 9.0 g of water needed to cool 500 g of liquid water from 20°C to 0°C?

Options

A.1
B.7
C.14
D.21

Solution

Heat lost by water = Heat gained by ice

$\text{Or, 500} \times \frac{75.6}{18} \times 20 = (N \times 9) \times \frac{6000}{18} \Rightarrow N = 14$

Create a free account to view solution

View Solution Free
Topic: Thermodynamics·Practice all Thermodynamics questions

More Thermodynamics Questions

In which of the following reactions, standard reaction entropy changes (ᐃSo) is positive and standard Gibb′s...Two moles of an ideal gas ($\gamma$ = 1.4) was allowed to expand reversibly and adiabatically from 1 L, 527°C to 32 L. T...For a process to occur under isothermal conditions, the essential condition(s) is/ are...The work done in an adiabatic change of fixed amount of an ideal gas depends on change in...A gas is heated at constant pressure. The fraction of heat absorbed used in doing work is...