A piece of alloy weighing 4 kg and at a temperature of 800 K is placed in 4 kg of water at 300 K. If

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A piece of alloy weighing 4 kg and at a temperature of 800 K is placed in 4 kg of water at 300 K. If the specific heat capacity of water is 1.0 cal/K-g and that of alloy is 4 cal/K-g, then the ΔSmix is (ln 2 = 0.7, ln 3 = 1.1, ln 7 = 1.95)

Accepted Answer

Heat lost by alloy = Heat gained by water

or 4 × 4 × (800 – T) = 4 × 1.0 × (T – 300) ⇒ T = 700 K

(As date is not given for vaporization of water)

Now, $\Delta S_{mix} = \Delta S_{alloy} + \Delta S_{water}$

$= 4 \times 4 \times \ln\frac{700}{800} + 4 \times 1 \times \ln\frac{700}{300} = 1.0\text{ K cal/K}$

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