The conductivity of a saturated solution of AgCl at 298 K was found to be 3.40 × 10−6 Ω−1 cm−1; the

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The conductivity of a saturated solution of AgCl at 298 K was found to be 3.40 × 10−6 Ω−1 cm−1; the conductivity of water used to make up the solution was 1.60 × 10−6 Ω−1 cm−1. Determine the solubility of AgCl in water in mole per litre at 298 K. The equivalent conductivity of AgCl at infinite dilution is 150.0 Ω−1 cm−2 eq−1.

Accepted Answer

$\Lambda_{eq} = \frac{\kappa}{C} \Rightarrow 150 	imes \frac{3.4 	imes 10^{- 6} - 1.6 	imes 10^{- 6}}{5}$$	herefore S = 1.2 	imes 10^{- 8}	ext{ mol c}	ext{m}^{- 3} = 1.2 	imes 10^{- 5}	ext{ M}$

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