ElectrochemistryHard

Question

For the cell reaction: 4Br− + O2 + 4H+ $\rightleftharpoons$ 2Br2 + 2H2O; E° = 0.18 V. The value of (log KC) at 298 K is [2.303 RT/F = 0.06]

Options

A.12
B.6
C.18
D.3

Solution

$E_{cell}^{o} = \frac{0.06}{n}.\log K_{eq} \Rightarrow 0.18 = \frac{0.06}{4}.\log K_{eq}$

$\therefore\log K_{c} = 12$

Create a free account to view solution

View Solution Free
Topic: Electrochemistry·Practice all Electrochemistry questions

More Electrochemistry Questions

Which is correct about fuel cells?...Mark out the correct statement(s) regarding electrolytic molar conductivity....When the sample of copper with zinc impurity is to be purified by electolysis, the appropriate electrode are...Given the ionic conductance of , K+, and Na+ are 74, 50 and 73 cm2 ohm-1 eq-1, respectively. The equivalent conductance ...The solution of CuSO4, in which copper rod is immersed, is diluted to 10 times. The reduction electrode potential...