ElectrochemistryHard

Question

Anthracene, C14H10, can be oxidized to anthraquinone, C14H8O2. What weight of anthraquinone can be produced by the passage of a current of 1 A of 40 min if the current efficiency is 96.5%?

Options

A.0.862 g
B.0.832 g
C.0.624 g
D.0.738 g

Solution

$C_{14}H_{10} + 2H_{2}O \rightarrow C_{14}H_{8}O_{2} + 6H^{+} + 6e^{-}$

$n_{eq}C_{14}H_{8}O_{2} = \frac{Q}{F} \Rightarrow \frac{w}{208} \times 6 = \frac{1 \times 40 \times 60 \times 0.965}{96500}$

∴ w = 0.832 gm

Create a free account to view solution

View Solution Free
Topic: Electrochemistry·Practice all Electrochemistry questions

More Electrochemistry Questions

AgNO3(aq.) was added to an aqueous KCl solution gradually and the conductivity of the solution was measured. The plot of...If 0.224 L of H2 gas is formed at the cathode, the volume of O2 gas formed at the anode under identical conditions, is...The standard reduction potentials Eo, for the half reactions are as Zn → Zn2+ + 2e-, Eo = + 0.76V Fe → Fe2+ ...The standard potentials of MnO4−|Mn2+ and MnO2|Mn2+ electrodes in acid solution are 1.51 and 1.23 V, respectively. Stand...During an electrolysis of conc. H2SO4, perdisulphuric acid (H2S2O8) and O2 form in equimolar amount. The amount of H2 th...