ElectrochemistryHard

Question

The molar conductivity of 0.10 M solution of MgCl2 is 100 mho cm2 mol−1, at 25°C. A cell with electrodes that are 1.50 cm2 in surface area and 0.50 cm apart is filled with 0.10 M – MgCl2 solution. How much current will flow when the potential difference between the electrodes is 5 volts?

Options

A.0.03 A
B.3.0 A
C.0.15 A
D.15 A

Solution

$\Lambda_{m} = \frac{\kappa}{C} = \frac{G.G^{*}}{C} \Rightarrow 100 = \frac{\frac{1}{R} \times \frac{0.5}{1.5}}{0.1 \times 10^{- 3}} \Rightarrow R = \frac{100}{3}\text{ ohm}$

$\text{Now, }V = IR \Rightarrow I = \frac{V}{R} = \frac{5}{100/3} = 0.15\text{ A}$

Create a free account to view solution

View Solution Free
Topic: Electrochemistry·Practice all Electrochemistry questions

More Electrochemistry Questions