ElectrochemistryHard

Question

For a electrochemical cell Zn|Zn2+ (C1 M)||Cu2+ (C2 M)|Cu, the decrease in free energy at a given temperature is a function of

Options

A.ln C1
B.ln C2
C.ln C2·C1
D.ln C1/C2

Solution

$- \Delta G_{cell} = nF.E_{cell} = nF\left\lbrack E_{cell}^{o} - \frac{RT}{nF}.\ln\frac{\left\lbrack Zn^{2 +} \right\rbrack}{\left\lbrack Cu^{2 +} \right\rbrack} \right\rbrack = nFE_{cell}^{o} - RT.\ln\frac{C_{1}}{C_{2}}$

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