ElectrochemistryHard
Question
The electrode potential of electrode
M(s) → Mn+ (aq) (2M) + ne-.
at 298 K is E1. When temperature is doubled and concentration is made half, then the electrode potential becomes E2. Which of the following represents the correct relationship between E1 and E2 ?
M(s) → Mn+ (aq) (2M) + ne-.
at 298 K is E1. When temperature is doubled and concentration is made half, then the electrode potential becomes E2. Which of the following represents the correct relationship between E1 and E2 ?
Options
A.E1 > E2
B.E1 < E2
C.E1 = E2
D.Cann′t be predicted
Solution
E1 = Eo - 
ln 2
E2 = Eo -
ln1 = Eo
∴ E2 > E1
ln 2E2 = Eo -
ln1 = Eo∴ E2 > E1
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