SolutionHard
Question
The vapour pressure of water is 12.3 kPa at 300 K. What is the vapour pressure of 1 molal aqueous solution of a non- volatile solute at 300 K?
Options
A.1.208 kPa
B.12.08 kPa
C.0.22 kPa
D.12.13 kPa
Solution
$P = X_{2}.P^{o} = \frac{1000/18}{1 + \frac{1000}{18}} \times 12.3 = 12.08\text{ K Pa}$
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