SolutionHard
Question
Consider a binary mixture of volatile liquids. If at XA = 0.4 the vapour pressure of solution is 580 torr then the mixture could be (pAo = 300 torr, pBo = 800 torr) :
Options
A.CHCl3 - CH3COCH3
B.C6 H5 Cl - C6 H5 Br
C.C6H6 - C6 H5 CH3
D.nC6 H14 - n C7 H16
Solution
It shows negative deviation from Raoult′s law
ps (actual) = 580 torr
ps (Raoult) = 0.4 × 300 + 0.6 × 800 = 600 torr.
ps (actual) = 580 torr
ps (Raoult) = 0.4 × 300 + 0.6 × 800 = 600 torr.
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