SolutionHard
Question
The molal boiling point elevation constant of water is 0.513°C kg mol−1. When 0.1 mole of sugar is dissolved in 200 g of water, the solution boils under a pressure of 1 atm at
Options
A.100.513°C
B.102.565°C
C.100.256°C
D.101.025°C
Solution
$\Delta T_{b} = K_{b}.m = 0.513 \times \frac{0.1}{200/1000} = 0.2565^{o}C$
∴ B.P. of solution = 100.2565°C
Create a free account to view solution
View Solution FreeMore Solution Questions
At $T(K),2$ moles of liquid A and 3 moles of liquid B are mixed. The vapour pressure of ideal solution formed is 320 mm ...1.8 gm of fructose is added to 2kg of water. The freezing point of the solution is :-(Kf = 1.86 K molality-1)...A quantity of 6.4 g sulphur dissolved in 200 g of CS2 raises the boiling point of the solvent by 0.32°C. Boiling point o...Ethylene glycol is used as an antifreeze in a cold climate. Mass of ethylene glycol which should be added to 4 kg of wat...Which of the following carbohydrates developes blue colour on treatment with iodine solution :-...