Ionic EquilibriumHard
Question
The acid ionization constant of Zn2+ is 2.0 × 10−10. What is the basic dissociation constant of Zn(OH)+?
Options
A.5 × 10–5
B.2.0 × 104
C.2 × 10–10
D.5 × 109
Solution
$K_{b} = \frac{Kw}{K_{a}} = \frac{10^{- 14}}{2 \times 10^{- 10}} = 5 \times 10^{- 5}$
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