Ionic EquilibriumHard
Question
The composition of an acidic buffer mixture made up of HA and NaA of total molarity 0.29 having pH = 4.4 and Ka = 1.8 × 10-5 in terms of concentration of salt and acid respectively is :
Options
A.0.09 M and 0.20 M
B.0.20 M and 0.09
C.0.1 M and 0.19 M
D.0.19 M and 010 M
Solution
pH = - log Ka + log 
Let a mol litre-1 be concentration of salt, then concentration of acid = (0.29 - a).
4.4 = - log 1.8 × 10-5 + log
∴ a = 0.09.
[Salt] = 0.09 M
[Acid] = 0.29 - 0.09 = 0.20 M.
Let a mol litre-1 be concentration of salt, then concentration of acid = (0.29 - a).
4.4 = - log 1.8 × 10-5 + log
∴ a = 0.09.
[Salt] = 0.09 M
[Acid] = 0.29 - 0.09 = 0.20 M.
Create a free account to view solution
View Solution FreeMore Ionic Equilibrium Questions
Solid BaF2 is added to a solution containing 0.1 mole of Na2C2O4 solution (1 L) until equilibrium is reached. If the Ksp...The conjugate base of [AI(H2O)3(OH)3] is :...0.1 millimole of CdSO4 are present in 10 mL acid solution of 0.08 N HCl. Now H2S is passed to precipitate all the Cd2+ i...Let the solubility of an aqueous solution of Mg(OH)2 be x then its ksp is...An amount of 0.15 mole of pyridinium chloride has been added into 500 ml of 0.2 M pyridine solution. Calculate pH of the...