Ionic EquilibriumHard
Question
A well is dug in a bed of rock containing fluorspar (CaF2). If the well contains 20000 L of water, what is the amount of F- in it ? Ksp = 4 × 10-11 (101/3 = 2.15)
Options
A.4.3 mol
B.6.8 mol
C.8.6 mol
D.13.6 mol
Solution
CaF2(s) Ca2+ + 2F-
s 2s
4s3 = Ksp = 4 × 10-11 ⇒ s = 2.15 × 10-4 M
So, amount of F- in 20000 lt of water = 2s × 20000 = 8.6 mol.
s 2s
4s3 = Ksp = 4 × 10-11 ⇒ s = 2.15 × 10-4 M
So, amount of F- in 20000 lt of water = 2s × 20000 = 8.6 mol.
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