Ionic EquilibriumHard
Question
The solubility of AgCl in water is 0.001435 g per litre at 15o C. The solubility product of AgCl is
(Ag = 108, Cl = 35.3)
Options
A.10−5
B.10−10
C.2 × 10−10
D.10−9
Solution
$S = \frac{0.001435}{143.5} = 10^{- 5}\text{ M}$
∴ Solubility product, Ksp = S2 = 10–10
Create a free account to view solution
View Solution FreeMore Ionic Equilibrium Questions
Which of the following solutions would have same pH?...100 mL of 0.02 M benzoic acid (pKa = 4.2) is titrated using 0.02 M NaOH. pH after 50 mL and 100 mL of NaOH have been add...The equilibrium constant of T2O (Tritium is an isotope of H) differ from those of H2O at 298 K. Let at 298 K, pure T2O h...A aqueous solution contains an unknown concentration of Ba2+. When 50 mL of a 1 M solution of Na2SO4 is added, BaSO4 jus...For the indicator thymol blue, the value of pH is 2.0 when half of the indicator is present in the unionized form. The p...