Ionic EquilibriumHard
Question
The solubility of AgCl in water is 0.001435 g per litre at 15o C. The solubility product of AgCl is
(Ag = 108, Cl = 35.3)
Options
A.10−5
B.10−10
C.2 × 10−10
D.10−9
Solution
$S = \frac{0.001435}{143.5} = 10^{- 5}\text{ M}$
∴ Solubility product, Ksp = S2 = 10–10
Create a free account to view solution
View Solution FreeMore Ionic Equilibrium Questions
Silver nitrate solution is gradually added to an aqueous solution containing 0.01 M each of chloride, bromide and iodide...The best indicator for the detection of end point in titration of a weak acid and a strong base is :...Hydrolysis of ester in presence of base :-...In the following reaction HC2O4- (aq) + PO43- (aq) HPO42-(aq) + C2O42-(aq), which are the two Bronsted bases?...When 10 mL of 0.1 M acetic acid (pKa = 5.0), is titrated against 10mL of 0.1 M ammonia solution (pKa = 5.0), the equival...