Ionic EquilibriumHard

Question

For the indicator thymol blue, the value of pH is 2.0 when half of the indicator is present in the unionized form. The percentage of the indicator in the unionized form in a solution of 4.0 × 10−3 M hydrogen ion concentration is

Options

A.40%
B.28.6%
C.71.4%
D.60%

Solution

$P^{H} = P^{K_{\ln}\log\frac{\left\lbrack \ln^{-}{} \right\rbrack}{\left\lbrack Hln\lbrack\rbrack \right\rbrack}}$

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