Ionic EquilibriumHard
Question
The equilibrium constant of T2O (Tritium is an isotope of H) differ from those of H2O at 298 K. Let at 298 K, pure T2O has pT (like pH) 7.60. What is the pT of a solution prepared by adding 100 ml of 0.4 M-TCl to 400 ml of 0.2 M-NaOT? (log 2 = 0.3)
Options
A.1.1
B.0.08
C.6.5
D.14.1
Solution
$\left\lbrack OT^{-} \right\rbrack_{\text{excess}} = \frac{400 \times 0.2 - 100 \times 0.4}{500} = 0.08\text{ M}$
$\therefore P^{OT} = - \log(0.08) = 1.1 $$$\text{Now, }PT = P^{Kw} - P^{OT} = 2 \times 7.60 - 1.1 = 14.1$$
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