Chemical EquilibriumHard

Question

The process 2A(g) $\rightleftharpoons$A2(g) has KP = 8 × 108 atm−1. If ‘A’ atoms are taken at 1 atm pressure, then what should be the equilibrium pressure of ‘A’?

Options

A.0
B.2.5 × 10−5 atm
C.4 × 104 atm
D.1.25 × 10−5 atm

Solution

2A(g) $\rightleftharpoons$ A2(g); KP = 8 × 108 atm−1

Initial partial pressure 1 atm 0

Partial pressure on complete reaction 0 0.5 atm

Equilibrium partial pressure 2x atm 0.5 – x ≈ 0.5 atm

Now, $8 \times 10^{8} = \frac{0.5}{P_{A}^{2}} \Rightarrow P_{A} = 2.5 \times 10^{- 5}\text{ atm}$

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