Chemical EquilibriumHard

Question

The process 2A(g) $\rightleftharpoons$A2(g) has KP = 8 × 108 atm−1. If ‘A’ atoms are taken at 1 atm pressure, then what should be the equilibrium pressure of ‘A’?

Options

A.0
B.2.5 × 10−5 atm
C.4 × 104 atm
D.1.25 × 10−5 atm

Solution

2A(g) $\rightleftharpoons$ A2(g); KP = 8 × 108 atm−1

Initial partial pressure 1 atm 0

Partial pressure on complete reaction 0 0.5 atm

Equilibrium partial pressure 2x atm 0.5 – x ≈ 0.5 atm

Now, $8 \times 10^{8} = \frac{0.5}{P_{A}^{2}} \Rightarrow P_{A} = 2.5 \times 10^{- 5}\text{ atm}$

Create a free account to view solution

View Solution Free
Topic: Chemical Equilibrium·Practice all Chemical Equilibrium questions

More Chemical Equilibrium Questions

(i) N2(g) + O2(g) ⇋ 2NO(g), K1(ii) N2(g) + O2(g) ⇋ NO(g) ; K2(iii) 2NO(g) N2(g) + O2(g) ; K3(iv) NO(g) &#865...The first and second dissociation constants of an acid H2A are 1.0 × 10-5 and 5.0 × 10-10 respectively.The ove...The equilibrium constant for the reaction N2(g) + O2(g) ⇋ 2NO(g) at temperature T is 4 × 10-4. The value of K...The equilibrium constant for some reactions are given below against each of the reaction.(i) 2N2 + 5O2$\rightleftharpoon...Consider the reaction equilibrium 2SO2(g) + O2(g) ⇋ 2SO3 (g); ᐃHo = - 198 kJ. On the basis of Le Chatelier&#...