Chemical EquilibriumHard
Question
Equilibrium constant for the following equilibrium is given at 0ºC.
Na2HPO4 . 12H2O (s) ⇋ Na2HPO4 . 7H2O (s) + 5H2O(g) KP = 31.25 × 10-13
At equilibrium what will be partial pressure of water vapour :
Na2HPO4 . 12H2O (s) ⇋ Na2HPO4 . 7H2O (s) + 5H2O(g) KP = 31.25 × 10-13
At equilibrium what will be partial pressure of water vapour :
Options
A.
× 10-3 atm
× 10-3 atmB.0.5 × 10-3 atm
C.5 × 10-2 atm
D.5 × 10-3 atm
Solution
Na2HPO4 .12H2O(s) ⇋ Na2HPO4.7H2O (s) + 5H2O (g) KP = 31.25 × 10-13
KP = (PH2O)5
(PH2O)5 = 31.25 × 10-13
(PH2O)5 = (3125)1/5 × (10-15)1/5
(PH2O)5 = 5 × 10-3
KP = (PH2O)5
(PH2O)5 = 31.25 × 10-13
(PH2O)5 = (3125)1/5 × (10-15)1/5
(PH2O)5 = 5 × 10-3
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