Chemical EquilibriumHard

Question

The formation constant of Ni(NH3)62+ is 6 × 108 at 250C. If 50 ml of 2.0 M NH3 is added to 50 ml of 0.20 M solution of Ni2+, the concentration of Ni2+ ion will be nearly equal to :

Options

A.3 × 10-10 mole litre-1
B.2 × 10-10 mole litre-1
C.2 × 10-9 mole litre-1
D.4 × 10-8 mole litre-1

Solution

        Ni+2     +    6NH3  →   [Ni (NH3)]+6         Kf  = 6 × 108
t = 0              0.01 mole   0.1 mole         0
Kc = = 6 × 108.    [Ni+2] =  4 × 10-8.

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