Chemical EquilibriumHard
Question
In the dissociation of N2O4 into NO2, (1 + α) values with the vapour densities ratio 
is as given by : [a-degree of dissociation, D-vapour density before dissociation, d-vapour density after dissociation]
is as given by : [a-degree of dissociation, D-vapour density before dissociation, d-vapour density after dissociation] Options
A.
B.
C.
D.
Solution
N2O4 ⇋ 2NO2 Mmix = 
1 - α 2α Mmix =
= (1 + α). Therefore, (A) option is correct.
1 - α 2α Mmix =
= (1 + α). Therefore, (A) option is correct.Create a free account to view solution
View Solution FreeMore Chemical Equilibrium Questions
An industrial fuel, ′water gas′ , which consists of a mixture of H2 and CO can be made by passing steam over...For the equilibrium LiCl·3NH3(s) $\rightleftharpoons$LiCl·NH3(s) + 2NH3(g); KP = 9 atm2 at 27°C. A 8.21 L vessel contain...The reactions PCl5(g) ⇋ PCl3(g) + Cl2(g) and COCl2(g) ⇋ CO(g) + Cl2(g) are simultaneously in equilibrium at ...The equilibrium constant for the reaction SO3(g) ⇋ SO2(g) + O2(g) is Kc = 4.9 × 10-2. The value of Kc for the...Consider the general reaction given below at 400 K$$xA(g) \rightleftharpoons yB(g) $$The values of $K_{p}$ and $K_{c}$ a...