Chemical EquilibriumHard

Question

A quantity of 34 g sample of BaO2 is heated to 1000 K in a closed and rigid evacuated vessel of 8.21 L capacity. What percentage of peroxide is converted into oxide? (Ba = 138)

2BaO2(s) $\rightleftharpoons$2BaO(s) + O2 (g); KP = 0.5 atm

Options

A.20%
B.50%
C.75%
D.80%

Solution

2BaO2(s) $\rightleftharpoons$2BaO(s) + O2(g)

$\frac{34}{170}\text{mole = 0.2}$

Equilibrium 0.2$x$ $x$ $\frac{x}{2}$

Now, $K_{p} = P_{O_{2}} \Rightarrow 0.5 = \frac{\frac{x}{2} \times 0.0821 \times 1000}{8.21}$

⇒ $x$ = 0.1

∴% of BaO2 decomposed = $\frac{0.1}{0.2} \times 100 = 50\%$

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