Chemical EquilibriumHard
Question
An amount of 1 mole each of A and D is introduced in 1 L container. Simultaneously the following two equilibria are established. A$\rightleftharpoons$B + C: KC = 106 M and B + D$\rightleftharpoons$A: KC = 10−6 M−1
Options
A.10−6 M
B.10−3 M
C.10−12 M
D.10−4 M
Solution
A $\rightleftharpoons$ B + C; K1 = 106
Initial moles 1 0 0
Equilibrium moles 1 – x + y x – y x
B + D $\rightleftharpoons$ A; K2 = 10–6
x 1 1
Equilibrium moles x – y 1 – y 1 + y – x
As K1 >> 1, we may assume x ≈ 1
Now, $K_{2} = \frac{(1 + y - x)}{(x - y)(1 - y)} \approx \frac{y}{(1 - y).(1 - y)}$
As K2 << 1, we may assume y << 1
$K_{2} = \frac{y}{(1 - y)(1 - y)} \simeq y $$$\therefore\lbrack A\rbrack = 1 - x + y \simeq y = 10^{- 6}\text{ M}$$
Create a free account to view solution
View Solution FreeMore Chemical Equilibrium Questions
For a reversible reaction A + B$\rightleftharpoons$C, if the concentrations of the reactants are doubled at a definite t...The following equilibrium are given CO + H2O ⇋ CO2 + H2 ----- K12H2 + O2 ⇋ 2H2O ------ K2then equilibrium co...When a mixture of N2 and H2 in the volume ratio of 1: 5 is allowed to react at 700 K and 103 atm pressure, 0.4 mole frac...For a reversible reaction $A\overset{\quad K_{1}K_{2}\quad}{\leftleftarrows}B$, the initial molar concentration of A and...Which of the following is/are correct statement(s)?...