Chemical EquilibriumMedium
Question
A gaseous mixture contains 0.30 moles of CO, 0.10 moles of H2, and 0.03 moles of H2O vapour and an unknown amount of CH4 per litre. This mixture is in equilibrium at 1200 K.
CO(g) + 3H2(g)$\rightleftharpoons$ CH4(g) + H2O(g); KC = 3.9
Options
A.0.39 M
B.0.039 M
C.0.78 M
D.0.078 M
Solution
$K_{C} = \frac{\left\lbrack CH_{4} \right\rbrack\left\lbrack H_{2}O \right\rbrack}{\lbrack CO\rbrack\left\lbrack H_{2} \right\rbrack^{3}} \Rightarrow 3.9 = \frac{\left\lbrack CH_{4} \right\rbrack \times 0.03}{0.3 \times (0.1)^{3}} \Rightarrow \left\lbrack CH_{4} \right\rbrack = 0.039\text{ M}$
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