Chemical EquilibriumMedium

Question

At T K, a compound AB2(g) dissociates according to the reaction 2AB2(g) $\rightleftharpoons$2AB(g) + B2(g), with a degree of dissociation ‘x’ which is small compared with unity. The expression for ‘x’ in terms of the equilibrium constant, KP and the total pressure P is

Options

A.$\frac{K_{p}}{P}$
B.$\left( K_{p} \right)^{1/3}$
C.$\left( \frac{2K_{p}}{P} \right)^{1/3}$
D.$\left( \frac{K_{p}}{P} \right)^{1/3}$

Solution

2AB2 $\rightleftharpoons$ 2AB + B2

1 0 0

Equilibrium 1 – x x x/2

$K_{p} = \frac{\left( \frac{x}{1 + \frac{x}{2}} \times P \right)^{2}.\left( \frac{x/2}{1 + \frac{x}{2}} \times P \right)}{\left( \frac{1 - x}{1 + \frac{x}{2}} \times P \right)^{2}} = \frac{x^{3}.P}{2(1 - x)^{2}\left( 1 + \frac{x}{2} \right)}$

$x < < 1,K_{p} = \frac{x^{3}.P}{2} \Rightarrow x = \left( \frac{2K_{p}}{P} \right)^{1/3}$

Heterogeneous Equilibrium

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