Chemical EquilibriumHard

Question

Solubility of a solute in a solvent (say, water) is dependent on the temperature as given by S = A.e–ΔH/RT, where ΔH is the heat of reaction: solute + H2O$\rightleftharpoons$solution. For a given solution, variation of log S with temperature is shown graphically. The solute should be

Options

A.CuSO4·5H2O
B.NaCl
C.Sucrose
D.CaO

Solution

$S = A.e^{- \Delta H/RT} \Rightarrow \ln s = \ln A - \frac{\Delta H}{RT}$

Positive slope represents that ΔH = negative.

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