For the reaction PCl5(g) $\rightleftharpoons$ PCl3(g) + Cl2(g), if initial moles of PCl5 is ‘x’, α i

Question

For the reaction PCl5(g) $\rightleftharpoons$ PCl3(g) + Cl2(g), if initial moles of PCl5 is ‘x’, α is the degree of dissociation and P is the total pressure at equilibrium, then $P_{PCl_{3}}.P^{- 1}$ is equal to

Accepted Answer

PCl5(g) $ightleftharpoons$ PCl3(g) + Cl2(g)X mole 0 0Equilibrium $x(1 - \alpha)$ $x.\alpha$ $x.\alpha$$P_{PCl_{3}} = \frac{x.\alpha}{x(1 + \alpha)} 	imes P \Rightarrow P_{PCl_{3}}.P^{- 1} = \frac{\alpha}{1 + \alpha}$

Question

Options

Solution

More Chemical Equilibrium Questions