Chemical EquilibriumHard
Question
For the reaction PCl5(g) $\rightleftharpoons$ PCl3(g) + Cl2(g), if initial moles of PCl5 is ‘x’, α is the degree of dissociation and P is the total pressure at equilibrium, then $P_{PCl_{3}}.P^{- 1}$ is equal to
Options
A.$\frac{x}{1 + x}$
B.$\frac{\alpha x}{\alpha + x}$
C.$\frac{\alpha}{1 + \alpha}$
D.$\frac{\alpha}{x + \alpha x}$
Solution
PCl5(g) $\rightleftharpoons$ PCl3(g) + Cl2(g)
X mole 0 0
Equilibrium $x(1 - \alpha)$ $x.\alpha$ $x.\alpha$
$P_{PCl_{3}} = \frac{x.\alpha}{x(1 + \alpha)} \times P \Rightarrow P_{PCl_{3}}.P^{- 1} = \frac{\alpha}{1 + \alpha}$
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