For the reaction I2(g) $\rightleftharpoons$2I(g), KC = 1.0 × 10−2 mol lit−1. What volume of the vess

Question

For the reaction I2(g) $\rightleftharpoons$2I(g), KC = 1.0 × 10−2 mol lit−1. What volume of the vessel should be taken so that at equilibrium 1 mole of I2 and 0.5 mole of ‘I’ are present at equilibrium?

Accepted Answer

$K_{C} = \frac{\lbrack Ibrack^{2}}{\left\lbrack I_{2} ightbrack} \Rightarrow 10^{- 2} = \frac{\left( \frac{0.5}{V} ight)^{2}}{\left( \frac{1}{v} ight)} \Rightarrow V = 25	ext{ L}$

Question

Options

Solution

More Chemical Equilibrium Questions