Chemical EquilibriumHard
Question
The equilibrium constant of the reaction SO2(g) + 1/2O2(g) ⇋ SO3(g) is 4 × 10-3 atm-1/2. The equilibrium constant of the reaction 2SO3(g) ⇋ 2SO2(g) + O2(g) would be :
Options
A.250 atm
B.4 × 103 atm
C.0.25 × 104 atm
D.6.25 × 104 atm
Solution
SO2(g) + 
O2(g) ⇋ SO3(g) Kp = 4 × 10-3
SO3 ⇋ SO2(g) +
O2(g) K′p = 
K′p =
2SO3 ⇋ 2SO2 + O2(g)
K″p = (K′p)2 =
= 6250 = 625×102 6.25 × 104 atm.
O2(g) ⇋ SO3(g) Kp = 4 × 10-3SO3 ⇋ SO2(g) +
O2(g) K′p = K′p =
2SO3 ⇋ 2SO2 + O2(g)
K″p = (K′p)2 =
= 6250 = 625×102 6.25 × 104 atm.Create a free account to view solution
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