Chemical EquilibriumHard

Question

One mole of ethanol is treated with one mole of ethanoic acid at 25oC. One-fourth of the acid changes into ester at equilibrium. The equilibrium constant for the reaction will be

Options

A.1/9
B.4/9
C.9
D.9/4

Solution

CH3COOH + C2H5OH $\rightleftharpoons$ CH3COOC2H5 + H2O

1 1 0 0

Equilibrium $1 - \frac{1}{4} = \frac{3}{4}$ $1 - \frac{1}{4} = \frac{3}{4}$ $\frac{1}{4}$ $\frac{1}{4}$

$K = \frac{\frac{1}{4} \times \frac{1}{4}}{\frac{3}{4} \times \frac{3}{4}} = \frac{1}{9}$

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