Mole ConceptHard
Question
A quantity of 1 kg of 1 m glucose solution is diluted to 5 kg. The molality of the diluted solution should be
Options
A.0.2 m
B.0.02 m
C.0.207 m
D.0.175 m
Solution
$1 \times \left( \frac{1000}{1000 + 1 \times 180} \times 1000 \right) = x \times \left( \frac{1000}{1000 + x \times 180} \times 5000 \right) \Rightarrow x = 0.175\text{ m}$
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