Mole ConceptHard

Question

A quantity of 27.6 g of K2CO3 was treated by a series of reagent so as to convert all of its carbon to K2Zn3[Fe(CN)6]2. The mass of the product formed is (K = 39, Zn = 65.4, Fe = 56)

Options

A.139.2 g
B.11.6 g
C.69.6 g
D.23.2 g

Solution

$12K_{2}CO_{3} \rightarrow K_{2}Zn_{3}\left\lbrack Fe(CN)_{6} \right\rbrack_{2}$

12 × 138 g 698.2 g

$\therefore 27.6g \frac{698.2}{12 \times 138} \times 27.6 = 11.64g$

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