Mole ConceptHard

Question

A quantity of 1 g of metallic carbonate XCO3 is completely converted into a chloride XCl2 weighing 1.11 g. The atomic mass of the element ‘X’ is

Options

A.10
B.20
C.30
D.40

Solution

$\frac{1}{A_{X} + 12 + 3 \times 16} = \frac{1.11}{A_{X} + 2 \times 35.5}$

⇒ Atomic mass of X, AX = 40.

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