Mole ConceptMedium
Question
The density (in g/L) of an equimolar mixture of methane and ethane at 1 atm and 0o C is
Options
A.1.03
B.2.05
C.0.94
D.1.25
Solution
Average molar mass of the mixture = $\frac{16 + 30}{2} = 23$
Hence, the density of mixture = $\frac{23}{22.4} = 1.03$
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