Mole ConceptHard
Question
A quantity of 6 g NaOH and 4.4 g CO2 is allowed to react to form Na2CO3 or NaHCO3 or both. Which of the following is correct statement regarding the reactions?
Options
A.NaOH is the limiting reagent if there is no any formation of NaHCO3.
B.NaOH is the limiting reagent if there is no any formation of Na2CO3.
C.Equal masses of Na2CO3 and NaHCO3 are formed if none of the reactant is left.
D.The total mass of reaction mixture will be 10.4 g after the end of reaction, in any possible case
Solution
(a) 2NaOH + CO2 → Na2CO3 + H2O
2 × 40 g 44 g
8 g ← 4.4 g
But NaOH is only 6 g and hence, L.R.
(b) NaOH + CO2 → NaHCO3
40 g 44 g
4 g ← 4.4 g
But NaOH is 6 g (excess). Hence, CO2 is L.R.
Create a free account to view solution
View Solution FreeMore Mole Concept Questions
Law of multiple proportions is not applicable for the oxide(s) of...A quantity of 1.4 g of a hydrocarbon gives 1.8 g water on complete combustion. The empirical formula of hydrocarbon is...In which of the following ways does an activated complex differ from an ordinary molecule ?...The energy of activation is :-...The number of g-molecules of oxygen in 6.023 × 1024 CO molecules is...