Mole ConceptHard

Question

Total number of electrons present in 4.4 g oxalate ion (C2O4 2–) is

Options

A.0.05NA
B.2.3NA
C.2.2NA
D.2.1NA

Solution

Number of electrons $= (2 \times 6 + 4 \times 8 + 2) \times \frac{4.4}{88} \times N_{A} = 2.3N_{A}$

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