Atomic StructureHard
Question
We wish to seen inside an atom. Assuming the atom to have a diameter of 10 pm, thismeans that one must be able to resolve a with of say 10 pm. if an electron microscope is used the minimum electron energy required is about
Options
A.1.5keV
B.15 keV
C.150keV
D.1.5MeV
Solution
From the de-Broglic equation,
λ =
where I is wavelength, h is plank’s constant and p is momentum and v is velocity
v =
= 7.25 × 107 m/s
∴ Energy of electron =
mv2
= 15 keV
λ =
where I is wavelength, h is plank’s constant and p is momentum and v is velocity
v =
= 7.25 × 107 m/s∴ Energy of electron =
mv2 = 15 keVCreate a free account to view solution
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