A neutron makes a head-on elastic collision with a stationary deuteron. The fractional energy loss o

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A neutron makes a head-on elastic collision with a stationary deuteron. The fractional energy loss of the neutron in the collision is

Accepted Answer

Let m be the mass of neutron, mass of deuteron will be 4m. So applying conservation of momentum,
mv + 0 = mv₁ + 2mv₂ & v - 0 = (v₂ + v₁) [Relative velocity of approach = relative of separation]
v₂ = v₁ + v
mv = mv₁ + 2m(v₁ + v) = 3mv₁ + 2mv - mv = 3mv₁

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