Photoelectric EffectMedium
Question
Number of photons of equal energy emitted per second by a 6 mW laser source operating at 663 nm is $\_\_\_\_$ .
(Given : $h = 6.63 \times 10^{- 34}$ J.s and $c = 3 \times 10^{8}\text{ }m/s$ )
Options
A.$5 \times 10^{16}$
B.$5 \times 10^{15}$
C.$10 \times 10^{15}$
D.$2 \times 10^{16}$
Solution
$P = \frac{nhC}{\lambda}$
$$6 \times 10^{- 3} = \frac{n \times 6.63 \times 10^{- 34} \times 3 \times 10^{8}}{663 \times 10^{- 9}} $$$n = 2 \times 10^{16}$ photons
Create a free account to view solution
View Solution FreeMore Photoelectric Effect Questions
Photoelectric effect experiments are performed using three different metal plates p, q and r having work functions φ...A particle of mass M at rest decays into two particles of masses m1 and m2, having non zero velocities. The ratio of the...The graph shows variation of stopping potential $V_{o}$ with the frequency $v$ of the incident radiation for three photo...The wavelength of x-ray photon is 0.01, its momentum in Kg m/sec is :...Protons and singly ionized atoms of U235 & U238 are passed in turn (which means one after the other and not at the same ...